Answer:
22.38 g of silicone-32 will be present in 300 years.
Step-by-step explanation:
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by
where,
= quantity of the substance remaining
= initial quantity of the substance
= time elapsed
= half life of the substance
From the information given we know:
- The initial quantity of silicone-32 is 30 g.
- The time elapsed is 300 years.
- The half life of silicone-32 is 710 years.
So, to find the quantity of silicone-32 remaining we apply the above equation
22.38 g of silicone-32 will be present in 300 years.
Answer:
The answer is 5/6.
Step-by-step explanation:
Lets start with a=1.
a+1=2, which is the denominator. (1/2)
Taking the same number as numerator, now, consider a=2.
a+1=3, denominator.(2/3)
Now, let a=3.
a+1==4, denominator for a=3. (3/4)
If continued a becomes equal to 4.
a+1=5, which is also the denominator. (4/5)
Now, since the denominator is 5, let a=5.
a+1=6, which will become the denominator. (5/6)
Thus the series follows a pattern of a/a+1.
Answer:
x = 2.3202
Step-by-step explanation:
Given equation:
on taking log both sides, we get
now,
using the property of log function
log(aᵇ) = b × log(a)
therefore,
we get
(3x-5)log(10) = xlog(7)
now,
log(10) = 1
and
log(7) = 0.84509
thus,
( 3x - 5 ) × 1 = 0.84509x
or
3x - 0.84509x - 5 = 0
or
2.15491x = 5
or
x = 2.3202
Answer:
$730.08
Step-by-step explanation:
22% = 0.22
1 - 0.22 = 0.78
Value after 2 years
v = 1200(0.78)²
v = 730.08
$730.08
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