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2 years ago

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Mathematics

1 answer:

Nat2105 [25]2 years ago

3 0

The answer is D plane Qpr

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PLEASE HELP ASAP! A mountain climber is at an altitude of 2.9 mi above the earth’s surface.

shutvik [7]

You can use Pythagorean theorm to solve.

$a^2 + b^2 = c^2$
C = 3959 + 2.9 = 3961.9

x = ???? = a
b = 3959
Plugin our data.
$a^2 + b^2 = c^2$
$a^2 + 3959^2 = 3961.9^2$
$a^2 + 15673681 = 15696651.61$
$a^2 = 22970.61$
$\sqrt{a^2} = sqrt{22970.61}$
$a = 151.560$
$x = 151.560$
$x = 151.6$

7 0

3 years ago

Three cube-shaped boxes are stacked one above the other. The volumes of two of the boxes are 1,331 cubic meters each, and the vo

Yuri [45]

31 is the total height of the stacked boxes.

3 0

3 years ago

Read 2 more answers

A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the

Lelu [443]

Answer:

95% Confidence interval: (0.375,0.377)

Step-by-step explanation:

We are given the following in the question:

Sample mean, $\bar{x}$ = 0.376 cc/cubic meter

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.0012

Degree of freedom =

$=n-1\\=15-1\\=14$

95% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.145$

$0.376 \pm 2.145(\dfrac{0.0012}{\sqrt{15}} )\\\\ = 0.376 \pm 0.0006\\\\ = (0.3754,0.3766)\approx (0.375,0.377)$

(0.375,0.377) is the required 95% confidence interval for the population mean potassium chloride concentration.

5 0

2 years ago

A football is kicked from the ground and follows the graph of the function y = –t2 + 3t, where y represents height and t represe

vesna_86 [32]

Answer:

The height of the objects are the same after 2 seconds.

Step-by-step explanation:

In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:

$-t^2 + 3t = -t + 4\\t^2 - 3t - t + 4 = 0\\t^2 - 4t + 4 = 0\\t_{1,2} = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*4}}{2*1} = \frac{4 \pm \sqrt{16 - 16}}{2}\\t_{1,2} = \frac{4}{2} = 2$

The height of the objects are the same after 2 seconds.

8 0

2 years ago

(6)(−3)(−5) ........................

My name is Ann [436]

Answer:

-2? maybe

Step-by-step explanation:

5 0

2 years ago