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2 years ago

PLEASE ANYONE HELP! DONT ANSWER IF UNSURE PLEASE

Mathematics

1 answer:

djverab [1.8K]2 years ago

4 0

Answer:

length 5cm, width 4cm, door width 2/5cm or. 4cm, length 10 ft, width 7.5 ft

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What is the x-value of point A? -6 -4 -2 4 6 X What’s the answer

olga nikolaevna [1]

Answer:

This is 8

Step-by-step explanation:

-6

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2 years ago

X3 - 3x^2- 54x + 112

Olegator [25]

Answer:

(x -2) (x- 8) (x+7)

Step-by-step explanation:

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2 years ago

Help and ill give brainliest

Furkat [3]

Answer:

No, it isnt a solution

Step-by-step explanation:

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2 years ago

A satellite dish is the shape of a paraboloid. The dish is 38 inches wide, and 10 inches deep. How many inches should the receiv

vitfil [10]

Answer:

9 in approx

Step-by-step explanation:

Step one:

given data

the shape of the satellite dish takes the form of a paraboloid.

the diameter of the dish is 38in wide

and 10 inches deep.

step two:

The expression for the paraboloid is

$4ay=x^2$

where y is the vertical axis of the paraboloid

a is vertex to focus.

and x is the radius of the dish

x= 38/2= 19in

substituting we have

$4a10 =19^2\\\\40a=361 \\\\$

divide both sides by 40

$a=361/40\\\\a=9.025$

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2 years ago

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.

Arada [10]

Answer:

a) $0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799$

$0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847$

The 95% confidence interval would be given by (0.799;0.847)

b) $n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79$

And rounded up we have that n=622

c) $n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11$

And rounded up we have that n=1068

Step-by-step explanation:

Part a

$\hat p=\frac{823}{1000}=0.823$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: