Answer: It is not possible that two triangles that are similar and not congruent in spherical geometry.
Step-by-step explanation:
For instance, taking a circle on the sphere whose diameter is equal to the diameter of the sphere and inside is an equilateral triangle, because the sphere is perfect, if we draw a circle (longitudinal or latitudinal lines) to form a circle encompassing an equally shaped triangle at different points of the sphere will definately yield equal size.
in other words, triangles formed in a sphere must be congruent and also similar meaning having the same shape and must definately have the same size.
Therefore, it is not possible for two triangles in a sphere that are similar but not congruent.
Two triangles in sphere that are similar must be congruent.
I don't know if it could be the area of a square but x has to be 8.34. (ROUNDED)
Answer : d. 438.5 ft
The diagram for the given statement is attached below.
Two sides AB and AC are equal so the angle B = angle C
WE know sum of three sides of a triangle = 180
angle A + angle B + angle C = 180
55 + B + C = 180
B + C = 180 -55 = 125
B and C are equal so we divide 125 by 2
angle B = 62.5 and angle C = 62.5
Now we apply sin law
150 * sin(55) = sin(62.5) * a
122.8728066 = sin(62.5) * a
a =
a= 138.52 feet
To find perimeter we add all the sides
150 + 150 + 138.52 = 438.52 feet
Answer:
40 Tickets
80 Tickets
Step-by-step explanation:
To find how many tickets it will take to break even, we use the formula:
Our variables are:
Fixed Cost = $200
Sales Price = $10
Variable Cost = $5
Let's plug in our values into the formula.
So the class needs to sell a total of 40 Tickets to break even.
Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.
Number of tickets for $200 profit = 40 x 2
Number of tickets for $200 profit = 80 Tickets.
So the class needs to sell 80 Tickets to make a $200 Profit.
Sorry I do not have added