Answer:
<em>The true statements are:</em>
<em>*The median weight for shelter A is greater than shelter B.</em>
<em>*The (IQR) interquartile range of shelter A is greater than the (IQR) interquartile range of shelter B.</em>
Step-by-step explanation:
<em>(for shelter A)</em>
median: 21
lowest value: 8
highest value: 30
lower quartile: 17
upper quartile: 28
(IQR) interquartile range: 28 - 17 = 11
Range: 30 - 8 = 22
<em>(for shelter B)</em>
median: 18
lowest value: 10
highest value: 28
lower quartile: 16
upper quartile: 20
(IQR) interquartile range: 20 - 16 = 4
Range: 28 - 10 = 18
~phew!, this took me long xd, hope this helps you~
I would highly appreciate it if you would mark me the brainliest~ :)
Answer:
with what do you need help? if you took a picture i cant see it at all
Step-by-step explanation:
So remember that percent means parts out of 100
60%=60/100=6/10
so every 10 throws she makes 6
how many 5 in 50?
50/10=5
answe ris 5
so 5 tens so therefor 5 sixes
5 times 6=30
answer is 30 throws
Answer:
The answer is ""
Step-by-step explanation:
Distance
midpoint height
let
Gradient
Perpendicular Gradient
midpoints
Similar to perpendicular
Now I'll obtain the perpendicular bisector solution
An equation of the center circle radius will be.
Answer:
The number of students that bring their lunches is 12
Step-by-step explanation:
Let
x -----> the number of students that bring their lunches
y -----> the total number of students in a class
we know that
The number of students that bring their lunches divided by the total number of students in a class must be equal to 3/8
-----> equation A
-----> equation B
substitute the value of y in equation A and solve for x
therefore
The number of students that bring their lunches is 12