There are 63 students in the room, this is because 21 time 3 gives you 63.
Answer:
The area of the shaded region is 21.45cm².
Slant height of tetrahedron is=6.53cm
Volume of the tetrahedron is=60.35
Given:
Length of each edge a=8cm
To find:
Slant height and volume of the tetrahedron
<u>Step by Step Explanation:
</u>
Solution;
Formula for calculating slant height is given as
Slant height=
Where a= length of each edge
Slant height=
=
=
=6.53cm
Similarly formula used for calculating volume is given as
Volume of the tetrahedron=
Substitute the value of a in above equation we get
Volume=
=
=
Volume=
=60.35
Result:
Thus the slant height and volume of tetrahedron are 6.53cm and 60.35
Hello!
The letter D is in the place for the upper quartile
To find this you have to find the median of the data
List the numbers from least to greatest
12, 18, 34, 55, 59, 68, 80, 80
The medians are 55 and 59
To get the median we take the average of these numbers
55 + 59 = 114
114 / 2 = 57
The median is 57
To find the upper quartile you find the median of the numbers higher than 57
List the numbers that are higher than 57 in the data
59, 68, 80, 80
Take the average of 68 and 80
68 + 80 = 148
148/2 = 74
The answer is 74
Hope this helps!
First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65
