Answer:
Cats and dogs are both mammals because they have hair, are warm-blooded, and nourish their young with milk. Dogs and cats are distinct species, incapable of producing offspring together because of the many differences in their genome.
Explanation:
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Answer: Because epinephrine activates the fight or flight response, related to the sympathethic response in the body.
Explanation:
The function of the Autonomic Nervous System is the regulation of the system cardiovascular, digestion, respiration, body temperature, metabolism, exocrine glands, and therefore keep the internal environment constant (homeostasis). While sympathetic activity increases in stress, the activity parasympathetic predominates during rest and satiety. The adrenal medulla originates from the neural crest and is composed of neuroendocrine specialized cells and are responsible for the production of catecholamines.
Catecholamines are dopamine, adrenaline, and noradrenaline (epinephrine and norepinephrine). Epinephrine prepares muscles, lungs, and heart for more intense activity, in situations of stress. It promotes the increase in the force of contraction in the muscles and increases in the heart rate. It also leads to increased blood pressure and bronchodilation, for greater availability of O2.
Controls what enters and leaves the cell
Answer:
812
Explanation:
You just want to multiply it by 100.
Answer:
0.549 is the frequency of the F allele.
0.495 is the frequency of the Ff genotype.
Explanation:
<em>FF </em>or <em>Ff</em> genotypes determine freckles, <em>ff</em> determines lack of freckels.
In this class of 123 students, 98 have freckles (and 123-98= 25 do not).
If the class is in Hardy-Weinberg equilibrium for this trait, then the genotypic frequency of the ff genotype is:
q²= 25/123
q²=0.203
q=
q= 0.451
<em>q </em>is the frequency of the recessive f allele.
Given <em>p</em> the frequency of the dominant F allele, we know that:
p+q=1, therefore p=1-q
p=0.549 is the frequency of the F allele.
The frequency of the Ff genotype is 2pq. Therefore:
2pq=2×0.549×0.451
2pq=0.495 is the frequency of the Ff genotype.