Answer:
Ok so the area of the frame is 18*12 = 216cm^2
Let’s suppose the width of the frame is x
The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432
4x^2 + 60x + 216 = 432
4x^2 + 60x - 216 = 0
x^2 + 15x - 54 = 0
(x+18)(x-3) = 0
Therefore x = {-18,3}
Since width of the frame has to be positive, the width has to be 3cm Step-
i hope i helped!
(9+w)w=252 or w(w+9)=252.
The quadratic equation applies: w²+9w-252=0=(w+21)(w-12), so w=12, because a negative zero is meaningless.
So the dimensions are width=12 in and length=21 in.
The correct answer is choice C. Here is the reason. If you substitute the information into the formula this is what it would be:
A = bh/2
13 = x (6x + 1)/2
13 = (6x^2 + x)/2
26 = 6x^2 + x
0 = 6x^2 + x - 26
Answer:
-2
Step-by-step explanation:
→ -9x + 1 = -x + 17
→ -9x + x = 17 - 1
→ -8x = 16
→ x = -16/8
→ [ x = -2 ]
Answer:
Step-by-step explanation:
To solve, first subtract 2x from both sides.
You appear to want the solution for -y, so I've included it. Given that you also want the solution for y, divide both sides by -1.
