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2 years ago

8

In a sixth grade classroom there are 15 car riders, 12 bus riders, and 3 walkers. What is the ratio of students that either are

car or bus riders to total students?

1 answer:

12345 [234]2 years ago

5 0

Answer:

For car riders, 15:30. For bus, 12:30. For walkers, 3:30

Step-by-step explanation:

Hope it helps

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Solve the system of equations below by elimination.<br> (Show your work)<br> 2x+3y=1<br> 5x+7y=3

nikdorinn [45]

Answer:

-2x+2y+3z=0

-2x-y+z=-3

2x+3y+3z=5

---------------

-2x+2y+3z=0

-2x-y+z=-3

---------------- Subtract

3y + 2z = 3 Eqn A

=========================

-2x-y+z=-3

2x+3y+3z=5

---------------- Add

2y + 4z = 2

6y + 4z = 6 Eqn A times 2

------------------------------------ Subtract

-4y = -4

y = 1

-----------------

z = 0

-------------------

x = 1

8 0

2 years ago

8 mi. 133 yd. 2 ft. – 5 mi. 107 yd. 2 ft.

Murrr4er [49]

8 mi. 133 yd. 2 ft. - 5mi. 107 yd. 2 ft.

= (8 mi. - 5 mi.) + (133 yd. - 107 yd) + (2 ft. - 2ft.)

= 3 mi. +26 yd.

<h3>= 3 mi. 26 yd.</h3>

8 0

2 years ago

Simplify the following expressions. All answers should be in standard form.

Ratling [72]

Answer:

The given expression in simplified form is: $15x^2+10x$

Step-by-step explanation:

Simplifying the expression involve reducing the number of terms to minimum and making the expressions in standard form.

This may involve addition, subtraction and multiplication of variables.

Given expression is:

$5x(3x+2)$

Distributing 5x will give us:

$= 5.3.x.x + 5.2.x\\=15x^2+10x$

Hence,

The given expression in simplified form is: $15x^2+10x$

6 0

2 years ago

Which of the following are factors of 6x^2+30x-36

stealth61 [152]

<span>6x^2+30x-36
= 6 (</span><span>x^2 + 5x - 6)
= 6 (x - 1)(x + 6)

hope it helps</span>

3 0

2 years ago

Read 2 more answers

Ierofanga [76]

Answer:

A

Step-by-step explanation:

Sum the product of the components in the first row of A with the corresponding components of the first column in B

Repeat this with the components in the second row of A with the corresponding components of the second column in B, that is

AB

= $\left[\begin{array}{ccc}2&1\\3&4\\\end{array}\right]$ $\left[\begin{array}{ccc}3&1\\5&2\\\end{array}\right]$

= $\left[\begin{array}{ccc}2(3)+1(5)&2(1)+1(2)\\3(3)+4(5)&3(1)+4(2)\\\end{array}\right]$

= $\left[\begin{array}{ccc}6+5&2+2\\9+20&3+8\\\end{array}\right]$

= $\left[\begin{array}{ccc}11&4\\29&11\\\end{array}\right]$ → A

6 0

2 years ago