Answer:
x3squared-3x2squared-18x
Step-by-step explanation:
1 Expand by distributing terms.
({x}^{2}-6x)(x+3)(x
2
−6x)(x+3)
2 Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd(a+b)(c+d)=ac+ad+bc+bd.
{x}^{3}+3{x}^{2}-6{x}^{2}-18xx
3
+3x
2
−6x
2
−18x
3 Collect like terms.
{x}^{3}+(3{x}^{2}-6{x}^{2})-18xx
3
+(3x
2
−6x
2
)−18x
4 Simplify.
{x}^{3}-3{x}^{2}-18xx
3
−3x
2
−18x
Answer:
1/3
Step-by-step explanation:
She has 18 ribbons in total and she has 6 pink ribbons so she has a 6/18 chance or 1/3 chance of pulling a pink ribbon
Answer:
B
Step-by-step explanation:
The value of the 4 in 14.8 is 10 times the value of the 4 in 3.46.
Answer:
x + 15
Step-by-step explanation:
Since I don't know what this number is, I'm going to use the variable x to substitute for the value of the unknown number.
So it would just be x + 15 because addition is the operation of adding and the key words are usually more. Since one of the numbers is unknown, we can't get an answer like "100" because x is undefined.
Say x=100, then the number would be written as 115 in it's simplest form but you could also write it as 100+15. So I'm just using substitution.
Answer:
<h2>There is 8% probability of Kitzen winning first and Ava second.</h2>
Step-by-step explanation:
The given table shows that there are 4 students, so there are 4 possible winner in total, but they have different number of tickets.
The total number of tickets is 48, that's the total possible outcomes. Kitzen has a probability of
Ava has a probability of
Now, the probability of having one event and the other is
Therefore, there is 8% probability of Kitzen winning first and Ava second.
(Notice that the probaility is not about Kitzen or Ava winning, it's about winning both, that's why the percentage is low)
