The molarity of the solution will be 3.45 M
<h3>Further explanation
</h3>
Dilution is the process of adding a solvent to get a more dilute solution.
The moles(n) before and after dilution are the same.
Can be formulated :
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
The initial solution
345 mL of a 2.5 M NaCl solution.
M₁=2.5 M
V₁=345 ml
The solution after boiled :
V₂=250 ml
![\tt M_2=\dfrac{M_1.V_1}{V_2}\\\\M_2=\dfrac{2.5\times 345}{250}\\\\M_2=3.45~M](https://tex.z-dn.net/?f=%5Ctt%20M_2%3D%5Cdfrac%7BM_1.V_1%7D%7BV_2%7D%5C%5C%5C%5CM_2%3D%5Cdfrac%7B2.5%5Ctimes%20345%7D%7B250%7D%5C%5C%5C%5CM_2%3D3.45~M)
The correct answer is B. An observation
Explanation:
An observation is defined as a statement or conclusion you made after observing or measuring a phenomenon, this includes statements based on precise instruments. For example, if you conclude a plant grows 2 inches every month by measuring the plant during this time, this is classified as an observation. The conclusion of the student is also an observation because he concludes this after analyzing the volume of the water in the cylinder through the lines in the graduated cylinder, considering the water is just in the middle of 100 mL and 200 mL which indicates there are 150 mL of water.
Names of Ionic Compounds<span>. </span>Name<span>. </span>CHEMISTRY<span>: A Study of Matter. © 2004, GPB. 6.16a. KEY. </span>Write<span> the </span>name<span> of </span>each ionic compound below. 1. MgS<span>. </span>2. FeO ... magnesium sulfide iron (II<span>) </span>oxide<span>barium sulfite </span>aluminum<span> hydroxide.</span>
Answer:
![-277.6\ \text{kJ/mol}](https://tex.z-dn.net/?f=-277.6%5C%20%5Ctext%7BkJ%2Fmol%7D)
Explanation:
Heat of combustion of
= -1366.8 kJ/mol
Heat of formation of
= -393.5 kJ/mol
Heat of formation of
= -285.8 kJ/mol
The reaction is
![C_2H_5OH(l)\rightarrow 2CO_2(g)+3H_2O(l)](https://tex.z-dn.net/?f=C_2H_5OH%28l%29%5Crightarrow%202CO_2%28g%29%2B3H_2O%28l%29)
Assuming
is the standard enthalpy of formation of ethanol
![-1366.8=2\times (-393.5)+3\times (-285.8)-x\\\Rightarrow x=2\times (-393.5)+3\times (-285.8)+1366.8\\\Rightarrow x=-277.6\ \text{kJ/mol}](https://tex.z-dn.net/?f=-1366.8%3D2%5Ctimes%20%28-393.5%29%2B3%5Ctimes%20%28-285.8%29-x%5C%5C%5CRightarrow%20x%3D2%5Ctimes%20%28-393.5%29%2B3%5Ctimes%20%28-285.8%29%2B1366.8%5C%5C%5CRightarrow%20x%3D-277.6%5C%20%5Ctext%7BkJ%2Fmol%7D)
The standard enthalpy of formation of ethanol is
.
Answer:
vague symptoms are characteristic of an acute toxin, because of the of the lack of well defined consistency that these symptoms have in relation to the course of the disease progress.