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2 years ago

Product of two integers is -6 and There sum is 1

Mathematics

1 answer:

dedylja [7]2 years ago

7 0

Answer:

3 and -2

Step-by-step explanation:

xy = -6

x + y = 1

let 'x' = y-1

y(y-1) = -6

y² - y + 6 = 0

(y-3)(y+2) = 0

y = 3 and -2

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Solve the right triangle, ΔABC, for all the missing side and angles to the nearest tenth given sides a = 10.6 and b = 19.2.

Aliun [14]

Answer:

Part 1) $c=21.9\ units$

Part 2) $B=61.1\°$

Part 3) $A=28.9\°$

Part 4) $C=90\°$

Step-by-step explanation:

step 1

Find the length side c

Applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

substitute the given values

$c^{2}=10.6^{2}+19.2^{2}$

$c^{2}=481$

$c=21.9\ units$

step 2

Fin the measure of angle B

we know that

In the right triangle

$tan(B)=b/a$

substitute the given values

$tan(B)=19.2/10.6$

$B=arctan(19.2/10.6)=61.1\°$

step 3

Find the measure of angle A

we know that

The measure of interior angles in a triangle must be equal to 180 degrees

∠A+∠B+∠C=180°

Remember that in a right triangle the measure of angle C is 90 degrees

we have

$B=61.1\°$

$C=90\°$

substitute

$A+61.1\°+90\°=180\°$

$A=28.9\°$

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Product of two integers is -6 and There sum is 1​

Product of two integers is -6 and There sum is 1