Okay, So We Need To First Remember The Rule About Means-To-Mad Ratios. It Is :
"You can use the means-to-MAD ratio to describe the similarity of two distributions. Divide the positive difference in the means by the larger of the two MAD values. If this ratio is 1 or less, the two distributions are similar. If this ratio is between 1 and 2.5, the two distributions are somewhat similar. If this ratio is greater than 2.5, the two distributions are different. "
So, Lets Use This Info. 2.1 Is Greater Than 1, So They Are Not Similar. It Is Greater Than 1 But Less Than 2.5, So, They Are Somewhat Similar. 2.1 Is Less Than 2.5, So They Are Not Different. They Cant Be Identical, Because That Would Mean It Is 0. So, This Means That The Answer Is They Are Somewhat Similar. I Hope This Helps!
Answer:
I think it is C.
Step-by-step explanation:
If I am correct may I please have brainliest?
Answer:
106
Step-by-step explanation:
Ok this question is a bit confusing but once you understand the concept you will be able to answer the question correctly
Always know that bracket is solved first once it is found in the question
So back to the question
-4(2-5)2+82
So let's get to work...
Bracket first
-4(-3)2+82
Multiply with the number at the front then followed by the one at the back
(+12)2+82
24+82
106
Therefore the final answer is 106
I believe you understand how we get the answer...just be careful when solving this kind of question... simple
Answer:
The average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to<em> x</em> = <em>a</em> + <em>h</em> is -3.
Step-by-step explanation:
We are given the function:
And we want to determine its average rate of change of the function for <em>x</em> = <em>a</em> and <em>x</em> = <em>a</em> + <em>h</em>.
To determine the average rate of change, we find the slope of the function between the two points. In other words:
Simplify:
In conclusion, the average rate of change of <em>g</em> from <em>x</em> = <em>a</em> to <em>x</em> = <em>a</em> + <em>h</em> is -3.
This is the expected result, as function <em>g</em> is linear, so its rate of change would be constant.