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2 years ago

Help need answer please

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

5 0

Answer:

59.5

Step-by-step explanation:

1st tree to shadow ratio: 17:10

Plug the numbers in to get x:35

17:10=x:35

17/10=x/35

Multiply both sides by 35

595/10=x

59.5=x

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In a study of brand recognition, 795 consumers knew of Amazon, and 10 did not. Use these results to estimate the probability tha

Rzqust [24]

Answer:

The probability that a randomly selected consumer will recognize Amazon is 0.988.

Step-by-step explanation:

The data given in the question is

Total number of consumers = 795 + 10 = 805

Consumers who knew of Amazon = 795

Consumers who did not know of Amazon = 10

The formula for calculating probability of an event A is:

P(A) = No. of favourable outcomes/Total no. of possible outcomes

P(Recognize Amazon) = No. of Consumers who knew Amazon/Total no. of consumers

P(Recognize Amazon) = 795/805

= 0.98757

P(Recognize Amazon) ≅ 0.988

The probability that a randomly selected consumer will recognize Amazon is 0.988.

7 0

2 years ago

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

2 years ago

What is the solution to the linear equation?

patriot [66]

Equation: 2/5 + p = 4/5 + 3/5p

Simplify Both Sides:
p + 2/5 = 3/5p + 4/5

Subtract 3/5p from both sides:
p + 2/5 - 3/5p = 3/5p + 4/5 - 3/5p

2/5p + 2/5 = 4/5

Subtract 2/5 from both sides:
2/5p + 2/5 - 2/5 = 4/5 - 2/5

2/5p = 2/5

Multiply both sides by 5/2

(5/2) * (2/5p) = (5/2) * (2/5)

p = 1

Answer: p = 1

Hope that helps!!! (Answer: Letter Choice (A), p = 1

8 0

2 years ago

I will mark you brainliest if you help me im not lying

aksik [14]

Answer:

60 miles

I hope this helps.

5 0

2 years ago

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I had 6 cupcakes two days ago, and 9 yesterday. help me continue this pattern. thank you.

lutik1710 [3]