Answer: No, the normal curve cannot be used.
Step-by-step explanation:
The theorem of the Normal approximation states that if X is B(n,p) then for large n X is N(np, np(1-p)).
The accuracy of this approximation is good
i. for n > [10/p(1-p)]
ii. p is close to 1/2
Hence given p= 4% = 0.04,
q = 1 - 0.04 = 0.96
Let N = [10/p(1-p)]
We find N = 10/p(1-p) = 10/(0.04× 0.96)
N ~= 260
Since n < 260 and p < 0.5
The approximation is not a good one
Answer:
y = 1
Step-by-step explanation:
4 - (y-3) = 3(y+1) - 4(1 - y)
4 -y +3 = 3y + 3 - 4 + 4y
7 - y = 7y - 1
7 + 1 = 7y + y
8 = 8y
8/8 = y
Answer:
Step-by-step explanation:
b , n, and a are variables so you cant solve but can be put in an equation which is b+a/n
54:36 is your answer.
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It should help
All the transformations for which A and B would be congruent are; Translation, Reflection, and Rotation.
<h3>What is congruence transformation?</h3>
A congruence transformation is defined as a movement of shape such that it can produce a shape that is congruent to the original.
There are three types of congruence transformation;
1. Translation
2. Reflection
3. Rotation
Given;
Shape B is made by applying a single transformation to shape A.
Hence, All the transformations for which A and B would be congruent are; Translation, Reflection, and Rotation.
Learn more about transformations ;
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