Answer:
Option (2). 1
Step-by-step explanation:
Coordinates of point A, B, C and D are,
A(-4, 4), B(-2, 4), C(-2, 1) and D(-4, 3).
Quadrilateral ABCD when rotated 90° clockwise about the origin,
Rule for the rotation of the vertices,
(x, y) → (y, -x)
Following the rule of rotation coordinates of the image points,
A(-4, 4) → A'(4, 4)
B(-2, 4) → B'(4, 2)
C(-2, 1) → C'(1, 2)
D(-4, 3) → D'(3, 4)
Since all image points have the positive coordinates (x and y coordinates), image quadrilateral A'B'C'D' will be located in 1st quadrant.
Option (2) is the correct option.
The 1st one :)
Jonah should shade 6 parts of 10
Answer:
the answer is C. No, it fails the vertical line test.
Answer:
<u>b(n) = -11 + (n-1)*8</u>
<u></u>
Step-by-step explanation:
Let n be the sequence number, with n=1 the first number b(1) -11
The sequence changes by +8 each step.
<u><em>b(1)</em></u><em> -11</em> + 8 = -3
<u><em>b(2)</em></u><em> -3</em> + 8 = 5
<u><em>b(3)</em></u> <em> 5 </em> + 8 = 13
<u><em>b(4)</em></u><em> </em> <em>13</em>
b(1) = -11
b(2) = -3. or b(1) + 1*8
b(3) = 5, or b(1) + 2*8
b(4) = 13, or b(1) + 3*8
We note that each step adds a multiple of 8 to the initial value of -11. This can be stated as (n-1)*8
The formula for this sequence would be b(n) = b(1) + (n-1)*8
<u>b(n) = -11 + (n-1)*8</u>
Check: Does n=3 return the value of 5?
b(n) = -11 + (n-1)*8
b(3) = -11 + ((3)-1)*8
b(3) = -11 + (2)*8
b(3) = -11 + 16
b(3) = 5 <u><em>YES</em></u>
<span>g(x) = –2x2 + 3x – 5
</span>input = –2, g(-2) = –2(-2)^2 + 3(-2) – 5 = -8 - 6 - 5 = -19
input = 0, g(0) = –2(0)^2 + 3(0) – 5 = -5
input = 3, g(3) = –2(3)^2 + 3(3) – 5 = -18 + 9 - 5 = -14
