<h3>
Answer: 80 degrees</h3>
============================================================
Explanation:
I'm assuming that segments AD and CD are tangents to the circle.
We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.
By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.
----------------------------
Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.
Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.
We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.
---------------------------
Here's what we have so far for quadrilateral DAEC
- angle A = 90
- angle E = 100
- angle C = 90
- angle D = unknown
Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees
A+E+C+D = 360
90+100+90+D = 360
D+280 = 360
D = 360-280
D = 80
Or a shortcut you can take is to realize that angles E and D are supplementary
E+D = 180
100+D = 180
D = 180-100
D = 80
This only works if AD and CD are tangents.
Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.
Answer:
32 days
Step-by-step explanation:
Assume that the jar is full initially, containing 24 oz. After how many withdrawals of 3/4 oz will the jar be empty?
24 - (3/4)n = 0, or
24 = (3/4)n, or 96 = 3n. Dividing both sides by 3, we get n = 32.
The jar will be empty after 32 days.
Answer:
I think the answer is 1/42
Hi there,
2/3 + w = 11/2
w = 11/2 - 2/3
Hence, W = 29/6
Hope this helps :)