2 years ago

what is the sum of the first 25 terms of an arithematic sequence if the sum of its 8th and 18th terms is 72?

Mathematics

1 answer:

max2010maxim [7]2 years ago

7 0

Answer:

900

Step-by-step explanation:

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aalyn [17]

Answer:

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Step-by-step explanation:

Apparently you want to simplify ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}$

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

1/a^b = a^-b

(a^b)^c = a^(bc)

So the expression simplifies as ...

$\sqrt{\dfrac{72x^{16}}{50x^{36}}}=\sqrt{\dfrac{36}{25x^{36-16}}}=\sqrt{\dfrac{36}{25x^{20}}}\\\\\sqrt{\left(\dfrac{6}{5x^{10}}\right)^2}=\boxed{\dfrac{6}{5x^{10}}}$

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2 years ago

what is the sum of the first 25 terms of an arithematic sequence if the sum of its 8th and 18th terms is 72?​

what is the sum of the first 25 terms of an arithematic sequence if the sum of its 8th and 18th terms is 72?