2 years ago

How much do the cars weigh? URGENT! I need this before tomorrow!

Mathematics

1 answer:

faltersainse [42]2 years ago

6 0

Answer:

Here is the short answer. The U.S. Environmental Protection Agency states that the average weight of a car in 2018 was 4,094 pounds.

Step-by-step explanation:

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Given that x = 5.4 m and 0 = 26°, work out BC rounded to 3 SF.

bagirrra123 [75]

Answer:

BC ≈ 4.85 m

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos26° = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AC}$ = $\frac{BC}{5.4}$ ( cross- multiply )

5.4 × cos26° = BC , then

BC ≈ 4.85 m ( to 3 s f )

4 0

2 years ago

Marathon Hours,Miles 0,0; 1,6; 2,11; 3,15; 4,21; 5,26.2. Cayla ran a marathon. The table shows which mile Cayla had finished at

stiv31 [10]

The answer would be B) 4mph

5 0

2 years ago

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In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

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2 years ago

Combine like terms 45Y +13 Y equals

Leya [2.2K]

Answer:

45Y + 13Y equals 58Y is the answer

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2 years ago

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The function c(x) = 3x − 4 determines how many cupcakes need to be purchased for a birthday party, where x is the number of kids

harina [27]

D(c(7))
so

c(7)=21-4=17

d(17)=34+5=39

39$

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2 years ago