Answer: shining a bright light on the object and testing for decomposition
Decomposition is the separation of a molecule into its elements or simpler compounds.
And a chemical property is the ability of a
substance to combine or to become one or more substances.
Then, testing the ability of an object for decomposition is testing a chemical property.
<u>Answer:</u> The correct answer is Option D.
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as 
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f_{(product)}]-\sum [n\times \Delta H^o_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28reactant%29%7D%5D)
Hence, the correct answer is Option D.
<span>A Homogeneous Catalyst exists in the same physical state as that of the reaction it catalyzes.
Explanation:
Catalysts are classifies as follow,
1. Homogeneous Catalyst
2. Heterogeneous Catalyst
</span>Homogeneous Catalyst are those which are in same phase as that of reactants are.
Example:
Acetic Acid + Ethanol + H₂SO₄ → Ethyl Acetate + H₂O + H₂SO₄
In this reaction catalyst and reactants all are in same phase i.e. Liquids.
Heterogeneous Catalyst are those which are in different phase as that of reactants are.
Example:
Ethene + H₂ + Ni → Ethane + Ni
In this reaction ethene and hydrogen are gases while Nickle catalyst is in solid state.
69. The student's skin was obviously warmer than the initial temperature of the bracelet. According to the second law of thermodynamics, heat transfers from a higher temperature to a lower temperature hence heat transfers from the student's skin to the bracelet warming up the bracelet.
70. moles of copper=mass of copper/molar mass of copper
=30.1g/(63.55g/mol)= 0.4736 moles Cu
71. Delta H( heat released) = mCp(deltaT) = 30.1g(0.385 J/gK)(33-19)K = 162.23J
72. Copper is chemically less active than iron.
Your answer should be c ph3
