Answer:
7.30167%
Step-by-step explanation:
Usando la fórmula de puntuación z
z = (x-μ) / σ, donde x es la puntuación bruta, μ es la media de la población y σ es la desviación estándar de la población
Para x <0.20 pulgadas
z = 0.20 - 0.25 / 0.02
z = -2.5
Valor de probabilidad de Z-Table:
P (x <0.20) = 0.0062097
Para x> 0.28 pulgadas
z = 0.28 - 0.20 / 0.02
z = 1.5
Valor de probabilidad de Z-Table:
P (x <0.28) = 0.93319
P (x> 0.28) = 1 - P (x <0.28) = 0.066807
La probabilidad de que se produzcan tornillos defectuosos cuando el tornillo se considera defectuoso si su diámetro es inferior a 0.20 pulgadas o superior a 0.28 pulgadas es
P (x <0.20) + P (x> 0.28)
= 0.0062097 + 0.066807
= 0.0730167
Conversión a porcentaje
= 0.0730167 × 100
= 7.30167%
El porcentaje de tornillos defectuosos producidos es
7.30167%
PEMDAS
2.5x + 0.1x = 2.6x
2.6x - 0.01x = 2.59x
Answer: 7/12
Step-by-step explanation:
number of times it landed on A = 6
number of times it landed on B = 21
number of times it landed on C = 9
Total number = 36
The empirical probability that the spinner will land on B is given by
P(B) = number of times it landed on B / Total number , that is
p(B) = 21/36
P(B) =7/12
Note: Empirical means verifiable by observation or experience rather than theory and it was verified that it landed on B 21 times.
It is going up by 5 so i believe your answer would be 57
18 - 5z + 6z > 3 + 6
18 + z > 9
- 18 - 18
z > -9
Solution Set: (-9, ∞)
