Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so .
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when .
So
A task time of 177.125s qualify individuals for such training.
Answer:
(10, 14)
Step-by-step explanation:
To solve this system let's use substitution:
Solve the first equation for x, obtaining x = 24 - y, and then substitute 24 - y for x in the second equation:
3(24 - y) + 5y = 100
Performing the indicated multiplication, we get:
72 - 3y + 5y = 100
Combining like terms results in 72 - 100 = -2y, or -28 = -2y
Thus, y must be 14.
If y = 14, then the first equation tells us that x = 10.
Check: Is this true? 3(10) + 5(14) = 100 YES
The solution is (10, 14).
What was it about the questions on the best that you were supposed to compare to this solution?
It's a slope-intercept form where a slope = -1.5 and y-intercept = 3.
x - intercept: y = 0
Therefore we have the equation:
-1.5x + 3 = 0 |-3
-1.5x = -3 |:(-1.5)
x = 2
Answer: x-intercept = 2, y-intercept = 3