Answer:
The required angle is (90-25)° = 65°
Explanation:
The given motion is an example of projectile motion.
Let 'v' be the initial velocity and '∅' be the angle of projection.
Let 't' be the time taken for complete motion.
Let 'g' be the acceleration due to gravity
Taking components of velocity in horizontal(x) and vertical(y) direction.
= v cos(∅)
= v sin(∅)
We know that for a projectile motion,
t =
Since there is no force acting on the golf ball in horizonal direction.
Total distance(d) covered in horizontal direction is -
d = ×t = vcos(∅)× = 
.
If the golf ball has to travel the same distance 'd' for same initital velocity v = 23m/s , then the above equation should have 2 solutions of initial angle 'α' and 'β' such that -
α +β = 90° as-
d = 
= ![\frac{v^{2}sin(2[90-β]) }{g}](https://tex.z-dn.net/?f=%5Cfrac%7Bv%5E%7B2%7Dsin%282%5B90-%CE%B2%5D%29%20%7D%7Bg%7D)
=
= 
.
∴ For the initial angles 'α' or 'β' , total horizontal distance 'd' travelled remains the same.
∴ If α = 25° , then
β = 90-25 = 65°
∴ The required angle is 65°.
Answer:
The boats are 934.65 feet apart
Explanation:
Given:
The angles of depression to the two boats are 42 degrees and 29 degrees
Height of the observation deck i = 1,353 feet
To Find:
How far apart are the boats (y )= ?
Solution:
<em><u>Step 1 : Finding the value of x(Refer the figure attached)</u></em>
We can use the tangent ratio to find the x value
x = 590.47 feet
<em><u>Step 2 : Finding the value of z (Refer the figure attached)</u></em>
z = 1525.12 feet
<em><u>Step 3 : Finding the value of y (Refer the figure attached</u></em>)
y = z -x
y = 1525.12 - 590.47
y = 934.65 feet
Thus the two boats are 934.65 feet apart
<h2>It solved by the Hooke's law states F=kx</h2>
answer is
<h2>0.4n/m</h2>
Answer:
Principle of conservation of linear momentum is state as provided no external force acts on a system of colliding bodies the total linear momentum of the bodies (in a given direction) remains constant
Wave speed= Frequency x Wavelength
-> Wavelength= Wave speed divide Frequency
-> 50m/s divide 100Hz= 0.5m
