The value of x is 34.64 feet
<h3>Right-angled triangle</h3>
Find the diagram attached
- The height of the tent = 40 ft
- length of the rope = x
Get the value of x using the SOH CAH TOA identity
Hence the value of x is 34.64 feet
Learn more on SOH CAH TOA here: brainly.com/question/20734777
Answer:
10. 7n - 1 < -8
Isolate the variable, n. Do the opposite of PEMDAS. Treat the < as equal sign, what you do to one side, you do to the other. First, add 1 to both sides:
7n - 1 (+1) < - 8 (+1)
7n < - 8 + 1
7n < - 7
Isolate the variable, n. Divide 7 from both sides:
(7n)/7 < (-7)/7
n < -7/7
n < -1
n < -1 is your answer.
11. 3 > -7v + 4v
Combine like terms, then isolate the variable, v. First, add -7v and 4v together.
3 > (-7v + 4v)
3 > (4v - 7v)
3 > (-3v)
Isolate the variable, v. Divide -3 from both sides. Note that since you are dividing a negative number, you must flip the sign:
(3)/-3 > (-3v)/-3
3/-3 > v
-1 < v
v > -1 is your answer.
~
Answer:
Height of the brick portion of the wall is 5.61 feet.
Step-by-step explanation:
Employees of the landscaping company used brick to build the top 2/3 of the wall. The total dimensions of the wall are 8 and 1/2 * 2 and 3/4 feet. So the height of the wall = 8 and 1/2 feet or in other words 8.75 feet.
Height of the brick portion of the wall = 2/3 * 8.5 = 0.66 * 8.5 = 5.61 feet
So the height of the brick portion of the wall is 5.61 feet.
Non brick portion of the wall is 8.5 - 5.61 = 2.89
Answer:
Step-by-step explanation:
C * D = {(x,y): x is an element of C and y is an element of D.}
C * D = { (1,4), (1,5), (1,6), (2,4), (2,5), (2,6) }
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
