Answer:
A) d = 11.8m
B) d = 4.293 m
Explanation:
A) We are told that the angle of incidence;θ_i = 70°.
Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;
tan 70° = d/4.3m
Where d is the distance from point B at which the laser beam would strike the lakebottom.
So,d = 4.3*tan70
d = 11.8m
B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)
So,
n1*sinθ_i = n2*sinθ_r
Thus; sinθ_r = (n1*sinθ_i)/n2
sinθ_r = (1 * sin70)/1.33
sinθ_r = 0.7065
θ_r = sin^(-1)0.7065
θ_r = 44.95°
Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;
d = 4.3 tan44.95
d = 4.293 m
Answer: A. 2.0m above ground
Explanation:
Height of the pitcher from the floor of his mound = 1.8m
Height of the mound above the rest of the field = 0.2m
Since the height difference between the mound and the ground the catcher stands on = 0.2m and the pitcher throws the ball horizontally, then the catcher has to hold his glove at (1.8 + 0.2)m
above ground.
= 2.0m above ground (option A)
B) the crust is much thinner from the other layers
Answer:
6
Explanation:
Given that
dsinθ = mλ,
now, if sinθ = 1, then
m = d / λ, where
m = order of interference
d = distance between the slits
λ = wavelength of light
this is the formula we would use to solve the question
d = 1 / 320 lines/mm
d = 1 / 320*10^3
d = 3.125*10^-6 m
At λ = 551 nm, we have
m = 3.125*10^-6 / 551*10^-9
m = 5.67
5.67 ~ 6
thus, we can say that the orders of visible wavelength 551 nm, can produce is 6
Answer:20.03 m/s
Explanation:
Given
velocity of Prototype 
Taking Froude number same for both flow as it is a dimensionless number for different flow regimes in open Flow
