Write "zero and five hundred one thousandths" as a decimal. nal

What are the zeroes of the polynomial equation? f(x) = x^2+9x+20

vredina [299]

Zeroes are when f(x)=0
0=x^2+9x+20
factor
0=(x+4)(x+5)
set each to zero
x+4=0
x=-4
x+5=0
x=-5

zeroes are f(-5) and f(-4)

7 0

2 years ago

Read 2 more answers

2 thirds divided by 4

hichkok12 [17]

1/6 or 0.16 in decimal form

3 0

2 years ago

The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 0 and x = 3.

Irina-Kira [14]

The average rate of change formula is basically the slope formula, where you plug in: f(b)-f(a)/b-a. Then plug in the numbers. [f(0)=1,f(3)=7)]. So, 7-1/3-0. 6/3 is 2 so the average rate of change is 2. And that makes sense because the average rate of change is always the slope, and the slope is 2.

3 0

2 years ago

For a production of sweeney todd in las vegas, orchestra seats cost $42 and mezzanine seats cost $25. if a group of 14 people sh

Lesechka [4]

Answer: 8 orchestra seats and 6 mezzanine seats.

Step-by-step explanation:

Let be "o" the number of orchestra seats they bought and "m" the number of mezzanine seats they bought.

Set up a system of equations:

$\left \{ {{42o+25m=486} \atop {o+m=14}} \right.$

You can apply the Substittution Method to solve the system of equations:

1. Solve for "o" from the second equation:

$o=14-m$

2. Substitute it into the first equation and solve for "m":

$42(14-m)+25m=486\\\\588-42m+25m=486\\\\-17m=-102\\\\m=\frac{-102}{-17}\\\\m=6$

3. Substitute the value of "m" into $o=14-m$ and evaluate, in order to find the value of "o". This is:

$o=14-6\\\\o=8$

4 0

2 years ago

Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral

MAVERICK [17]

Answer:

a. $\frac {2} {s-1}$ converges to s> 1.

b. $\frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $- \frac {2}{s + 3}$ converges to s> - 3.

d. $\frac {s}{s^2 + 25}$ converges to s> 0.

e. $\frac {10} {s^2 + 1}$ converges even s> 0.

f. $\frac {12}{s^2 + 4}$ converges to s> 0.

g. $-\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $\frac {1} {s ^ 2 + 4}$ converges to s> 0.

Step-by-step explanation:

a. $L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1}$ converges to s> 1.

b. $L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)}$ converges to s> 5.

c. $L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3}$ converges to s> - 3.

d. $L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25}$ converges to s> 0.

e. $L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1}$ converges even s> 0.

f. $L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4}$ converges to s> 0.

g. $L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4}$ converges to s> 0.

h. $L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4}$ converges to s> 0.

7 0

3 years ago