1 ) first offer
total payments
375.76×12×4
=18,036.48
Interest paid
18,036.48−16,000
=2,036.48
Second offer
Total payments
390.61×12×4
=18,749.28
Interest paid
18,749.28−16,000
=2,749.28
Larry will save of taking 6% loan
2,749.28−2,036.48=712.8. .answer
2) credit card 1
Total payments
277.09×12
=3,325.08
Interest paid
3,325.08−3,000
=325.08
Credit card 2
Total payments
152.69×12×2
=3,664.56
Interest paid
3,664.56−3,000
=664.56
Susan will save
664.56−325.08
=339.48...answer
Hope it helps!
Answer:
6,7
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The data is skewed, and the lowest number of crackers in a package was 7
Let x=annual interest rate of 18000 investment.
Then
18000*x - 9000(x-0.006)=648
Solve for x
18000x-9000x+9000*0.006=648
9000x=648-54=594
x=594/9000=0.066
Answer:
the annual interest rate of the 18000 investment is 6.6%
the annual interest rate of the 9000 investment is 6.0%
No. 6r is 6 multiplied by r so in order to get r, you will need to divide both sides by 6 in the first equation so r should =12