Answer:
b
Step-by-step explanation:
Answer:
7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg
8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg
Step-by-step explanation:
Law of Cosines
You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.
Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.
7.
We use the law of cosines to find C.
Now we use the law of sines to find angle A.
Law of Sines
We know c and C. We can solve for a.
Cross multiply.
To find B, we use
m<A + m<B + m<C = 180
40.8 + m<B + 78.6 = 180
m<B = 60.6 deg
8.
I'll use the law of cosines 3 times here to solve for all the angles.
Law of Cosines
Find angle A:
Find angle B:
Find angle C:
Answer:
A
C
D
E
Step-by-step explanation:
Exterior angles can be described as the angles that are formed between the side of a polygon and the extended adjacent side of the polygon.
Or an exterior angle is the angle that is not inside the triangle formed.
The angles inside the triangle are interior angles.
Exterior angles are :
2
3
4
6
Interior angles are :
1
5
I am sorry i dont understand
Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°