Question

Much power does a 10 Ohm bulb have in a series circuit with a battery of 12V and nothing else in the the circuit?

Answer 1

Answer:

it will be d) 14.4W

Explanation:

potential difference (v) = 12 volts

resistance (r) = 10 ohms

now, we know

=》

$power = \frac{v {}^{2} }{r}$

=》

$power \: = \frac{12 {}^{2} }{10}$

=》

$power = \frac{144}{10}$

=》

$power = 14.4 \: watt$