Answer:
C. An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele
Explanation:
Assuming the black genotype is BB and the brown genotype is bb.
At F1:
BB x bb = All Bb (black)
At F2:
Bb x Bb = BB (black), 2Bb (Black), bb (brown)
Th ratio of black to brown is 3:1
961 black : 317 brown is approximately 3:1.
Hence, the correct option is C.
<em>An approximately three-to-one ratio of black to brown coated mice in F2 is accounted for by the black allele being dominant over the brown allele</em>
Answer: Here's The Cell Cycle Concept Map
I think it's d but I'm not sure!!
You can use a chromosomal karyotype to see if there are any abnormalities with the normal 23 pairs of chromosomes that every healthy human has. Different abnormalities like an extra chromosome (trisomy), missing a chromosome (Minos omg), or having certain parts missing or added on can lead to a person to be diagnosed with certain disease (ex: Down syndrome is an extra chromosome on the 21st chromosome).
Hope this helps!
The renal medulla is made for the most part out of gathering channels and the nephron circles. You won't perceive any glomeruli in the medulla, as they are restricted to the cortex. This makes the renal cortex and renal medulla effortlessly recognizable.