6(4x + 2) = 3(8x + 4)
Reorder the terms:
6(2 + 4x) = 3(8x + 4)
(2 * 6 + 4x * 6) = 3(8x + 4)
(12 + 24x) = 3(8x + 4)
Reorder the terms:
12 + 24x = 3(4 + 8x)
12 + 24x = (4 * 3 + 8x * 3)
12 + 24x = (12 + 24x)
Add '-12' to each side of the equation.
12 + -12 + 24x = 12 + -12 + 24x
Combine like terms: 12 + -12 = 0
0 + 24x = 12 + -12 + 24x
24x = 12 + -12 + 24x
Combine like terms: 12 + -12 = 0
24x = 0 + 24x
24x = 24x
Add '-24x' to each side of the equation.
24x + -24x = 24x + -24x
Combine like terms: 24x + -24x = 0
0 = 24x + -24x
Combine like terms: 24x + -24x = 0
0 = 0
Solving
0 = 0
<span><span>Solve the system for x and y.</span><span>2y = x + 8</span><span>2y − 10 = 2x</span> <span>A) x = </span>−<span>3, y = 2</span> <span>B) x = </span>−<span>2, y = 3</span> <span>C) x = </span>−<span>5, y = 2</span> <span>D) x = 0, y = -5</span></span>
If f(x) = (6x-11), then f(-6) = -47.
We are provided in the question statement with a function "f(x)" whose output is a polynomial of 1 variable and degree 1.
To obtain the value of f(-6) from the output polynomial of the function f(x), we will simply need to substitute (-6) as the value of x in the polynomial and calculate the final value.
So,
![f(-6)=[(6*(-6))-11]\\or, f(-6)=(-36-11)\\or, f(-6)=-(36+11)\\or, f(-6) =-47](https://tex.z-dn.net/?f=f%28-6%29%3D%5B%286%2A%28-6%29%29-11%5D%5C%5Cor%2C%20f%28-6%29%3D%28-36-11%29%5C%5Cor%2C%20f%28-6%29%3D-%2836%2B11%29%5C%5Cor%2C%20f%28-6%29%20%3D-47)
Hence, f(-6) = -47.
- Polynomial: In mathematics, an expression of more than two algebraic terms, especially the sum of several terms that contain the same variable(s) of different powers and individual, distinct co-efficients.
- Function: In Mathematics, a function is an operator which on taking input, provides a certain output.
To learn more about Polynomials and Functions, click on the link below.
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Answer:
Step-by-step explanation:
You are to make 5 assemblies.
Each assembly requires the use of 1 Type A bolt.
To make the 5 assemblies, you need 5 Type A bolts.
The container of bolts has a total of 60 bolts.
The focus - Type A bolts - is 20 out of this 60.
The probability of obtaining a Type A bolt at all, is 20/60, which is = 1/3
(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?
- The exact number of Type A bolts you need for the 5 assemblies is 5
1/3 × 5/10 = 5/30 = 1/6 = 0.167
(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:
1/3 × 4/10 = 0.133
1/3 × 3/10 = 0.1
1/3 × 2/10 = 0.067
1/3 × 1/10 = 0.033
1/3 × 0/10 = 0
TOTAL = 0.333
Answer: it is linear because no bumps.
Step-by-step explanation:
