The solution for the problem is:
I will first get the first five terms so that I could easily locate the third term of this problem:So, substituting the values:
T(1) = 1^2 = 1T(2) = 2^2 = 4T(3) = 3^2 = 9T(4) = 4^2 = 16T(5) = 5^2 =25
So the third terms is T(3) = 3^2 = 9
D. y = 6x...subbing in (2,12)...x = 2 and y = 12
12 = 6(2)
12 = 12 (correct)
so (2,12) is a solution to : y = 6x
Answer:
C)
Step-by-step explanation:
Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.
All the given options for the line of best fit are linear equations.
Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.
Linear equation:
(where is the slope and is the y-intercept)
From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 8. So this suggests that options C or D are the solution.
We can also see that the slope (gradient) of the line of best fit is approximately -0.5 (as the rate of change (y/x) is -1 unit of y for every +2 units of x).
Therefore, C is the solution, and the closet approximation to the line of best fit is
Answer:
∠ 5 = 49°, ∠ 6 = 131°
Step-by-step explanation:
∠ 5 and 49° are corresponding angles and are congruent, then
∠ 5 = 49°
∠ 5 and ∠ 6 are adjacent angles and are supplementary, sum to 180° , that is
∠ 6 + ∠ 5 = 180°
∠ 6 + 49° = 180° ( subtract 49° from both sides )
∠ 6 = 131°