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2 years ago

188.49 rounded to the nearest 10th

Mathematics

2 answers:

ipn [44]2 years ago

7 0

Answer:

188.49 rounded = 188.50

Aleksandr-060686 [28]2 years ago

3 0

Answer:

Step-by-step explanation:

188.5

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Simplify the expression 3x(4x^4 - 5x)

Soloha48 [4]

3x (4x^4-5x)
add all of the numbers with a x to get
12x^4
and 12x^4=
20736x

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2 years ago

which property is shown? 20×5×6=20×6×5 A commutative property B distibutivr C associative property or D none of these are correc

Contact [7]

A: communicative property, it is this because communicative property allows you to switch around the order.

5 0

2 years ago

The graph shows a system consisting of a linear equation and a quadratic equation.

Lorico [155]

Answer:

(3, 4) and (5, 12)

Step-by-step explanation:

The points where the two curves intersect are the solutions to the system of equations:

(3, 4) and (5, 12)

3 0

3 years ago

A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par

ElenaW [278]

The equation of the central street PQ is -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

$-7x+3y=-21.5$

Convert it to the general form given below:

$\rm y=mx+c$

$\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x$ or

$\rm y = \frac{7}{3}x-\frac{21.5}{3}$

$m = \frac{7}{3}$ (Slope of AB line)

For the slope(m') of the PQ line:

$\rm m'=-\frac{1}{m}$ ( because AB and PQ are perpendicular to each other)

$\rm m' = -\frac{3}{7}$

We know the:

$\rm (y-y')=m'(x-x')$

Where (x', y') = (7, 6), we get:

$\rm (y-6)=-\frac{3}{7} (x-7)$

$\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63$

$\rm -1.5x-3.5y=-31.5$ (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is -1.5x - 3.5y = -31.5

Learn more about the straight line.

brainly.com/question/3493733

6 0

1 year ago

The motorcycle engine on a kawasaki ninja 1000 has a displacement of 1043 cubic-centimeters (cm3). in order to calculate its eng

marishachu [46]

$\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}$

<h3>Further explanation</h3>

We will calculate the unit conversion factor used to convert its engine displacement from cubic-centimeters to cubic-inches.

The relationships between inch and cm are as follows:

$\boxed{ \ 1 \ inch = 2.54 \ cm\ }$

Inches and cm represent units of length.

Made into fractions, 1 inch as the denominator and 2.54 cm as the numerator.

$\boxed{ \ \frac{1 \ inch}{2.54 \ cm} \ }$

As a unit conversion factor of volume, the numerator and the denominator in cubic.

$\boxed{ \ \frac{(1 \ inch)^3}{(2.54 \ cm)^3} \ }$

$\boxed{ \ \frac{1 \ inch^3}{16.387 \ cm^3} \ }$

Thus, we get the unit conversion factor

$\boxed{\boxed{ \ 0.061 \frac{inch^3}{cm^3}\ }}$

Let's use this unit conversion factor to calculate its engine displacement in new units.

$\boxed{= 1,043 \ cm^3 \times 0.061 \ \frac{inch^3}{cm^3}}$

Note for cm³ units that have been crossed out.

The conversion result is $\ \boxed{ \ 63.623 \ inch^3\ }$

<h3>Learn more</h3>

Convert cubic-kilometers to cubic-meters brainly.com/question/1446243
How to write in scientific notation brainly.com/question/7263463
Calculating mass based on density and volume brainly.com/question/4053884

Keywords: the motorcycle engine, Kawasaki Ninja 1000, 1043 cubic-centimeters (cm³), to calculate, its engine displacement, in cubic-inches (in³), what unit conversion factor

5 0

2 years ago

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