We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
Answer:
c
Step-by-step explanation:
i dont really have an explanation but i got it right
To find the slope and the -intercept of the line, first write the function as an equation, by substituting for
y=10
y=0x+10
y=0x+10 , m=0
y=0x+10 , m=0 , b=10
m=0 , b=10
The slope of the line is m=0 and the y-intercept is b=10
I think it is 47 not sure
