All categories

2 years ago

(i will give brain+40 points) i will need a step by step so i can write it down aswell

Mathematics

2 answers:

Zanzabum2 years ago

8 0

Answer: If they were all the same size then what would that shape be it wouldn't be a shape at all.

andrew-mc [135]2 years ago

3 0

Here,
Let the shortest side be “x” and let the triangle be ABC
So,
AB= x
BC=x+2
CA=2x
Now,
Perimeter=AB+BC+CA
166= x+(x+2)+2x
166=4x +2
164=4x
x=164/4
x=41
Therefore the length of the shortest side is 41cm

You might be interested in

A robot can complete 5 tasks in 2/3 hour. Each task takes the same amount of time.

melisa1 [442]

Answer:

a. 8 minutes

b. 7.5 tasks

Step-by-step explanation:

$\frac{2}{3}$ of an hour is just 40 minutes.

Let's use a ratio:

minutes : tasks

40 : 5

8 : 1

20 : 2.5

60 : 7.5

a. 8 minutes

b. 7.5 tasks

4 0

2 years ago

Help!!!! Its A Math Question Which of the following equations describes the relationship for the values in the table.

Sedbober [7]

Answer:

$y = 10 \times - 1 =$

$\times - 1 = - 10$

$- 10$

8 0

1 year ago

Plot 1 1/5, 1 on graph

Irina-Kira [14]

Find 1 on the x axis and go up 1 on the y axis.
Find 5 on the x axis and go up 1. you should now have two plotted points

7 0

2 years ago

Which expression is a fourth root of -1+isqrt3?

aleksklad [387]

Answer:

Step-by-step explanation:

$\sf n^{th}$ roots of a complex number is given by DeMoivre's formula.

$\sf \boxed{\bf r^{\frac{1}{n}}\left[Cos \dfrac{\theta + 2\pi k}{n}+i \ Sin \ \dfrac{\theta+2\pi k}{n}\right]}$

Here, k lies between 0 and (n -1) ; n is the exponent.

$\sf -1 + i\sqrt{3}$

a = -1 and b = √3

$\sf \boxed{r=\sqrt{a^2+b^2}} \ and \ \boxed{\theta = Tan^{-1} \ \dfrac{b}{a}}$

$\sf r = \sqrt{(-1)^2 + 3^2}\\\\ = \sqrt{1+9}\\\\=\sqrt{10}$

$\sf \theta = tan^{-1} \ \dfrac{\sqrt{3}}{-1}\\\\ = tan^{-1} \ (-\sqrt{3})$

$\sf = \dfrac{-\pi }{3}$

n = 4

For k = 0,

$\sf z = \sqrt[4]{10}\left[Cos \ \dfrac{\dfrac{-\pi}{3} +0}{4}+iSin \ \dfrac{\dfrac{-\pi}{3}+0}{4}\right] \\\\\\z= \sqrt[4]{10} \left[Cos \ \dfrac{ -\pi }{12}+iSin \ \dfrac{-\pi}{12}\right]\\\\\\z = \sqrt[4]{10}\left[-Cos \ \dfrac{\pi}{12}-i \ Sin \ \dfrac{\pi}{12}\right]$

For k =1,

$\sf z = \sqrt[4]{10}\left[Cos \ \dfrac{5\pi}{12}+i \ Sin \ \dfrac{5\pi}{12}\right]$

For k =2,

$z = \sqrt[4]{10}\left[Cos \ \dfrac{11\pi}{12}+i \ Sin \ \dfrac{11\pi}{12}\right]$

For k = 3,

$\sf z = \sqrt[4]{10}\left[Cos \ \dfrac{17\pi}{12}+i \ Sin \ \dfrac{17\pi}{12}\right]$

For k = 4,

$\sf z =\sqrt[4]{10}\left[Cos \ \dfrac{23\pi}{12}+i \ Sin \ \dfrac{23\pi}{12}\right]$

4 0

1 year ago

2. Find the value of x. (1 point) (5x) (3x+28) O 14 O20 O 12 O 19

nata0808 [166]

Answer:

x = 14

Step-by-step explanation:

The triangle has 2 congruent legs and is isosceles with 2 base angles being congruent , then

5x = 3x + 28 ( subtract 3x from both sides )

2x = 28 ( divide both sides by 2 )

x = 14

6 0

2 years ago