Rosa made a mosaic wall mural using 47 black tiles, 36 blue tiles and 17 red tiles.

There are 112 seats in the school auditorium. There are 7 seats in each row. There are 70 people seated,filling up full rows of

lord [1]

I think 11 rows are empty.

6 0

2 years ago

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What 2-dimensional shape would be formed by a perpendicular cross section of a soda can

Stella [2.4K]

Answer:

Rectangle

Step-by-step explanation:

We know that soda can is made in the cylinder shape when we cut a soda can in perpendicular cross section we get a 2D shape of Rectangle.

3 0

2 years ago

13x -2y -5x +8

Sati [7]

Step-by-step explanation:

1. How many terms are in the expression?

The terms are sorted by looking at the sing/indicator in front of them. For this expression there are 4 terms

13x, -2y, -5x, and 8

2. Which terms are “like terms”?

13x and -5x are like terms.

3. Are there any constants? If so, what are they?

Yes there is a constant terms and it's 8

4. What are the variables in the expression?

The variables in this expression are x, and y

5. What are the coefficients in the expression?

Coefficients is the number in front of variables in this expression the coefficients are 13, -2, and -5

6 0

2 years ago

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Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

2 years ago

Please help!!!<br> 20 points

mrs_skeptik [129]

Answer:

c

Step-by-step explanation:

4 0

2 years ago

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