6 - 2 2/7 =
6 - 16/7 =
42/7 - 16/7 =
26/7 or 3 5/7
The explorer's running velocity will be 1/3 the velocity of the train, 45/3 = 15.
From those issue statement, the train will a chance to be at the begin of the span The point when those voyagers have run 1/3 of the period of the span. In they run of the much end of the bridge, they will bring run 1/3 of the length of the span when those prepare achieves the close to wind. Beginning starting with those 1/3 point, they will make toward those 2/3 perspective At those prepare achieves those span. The prepare will travel the full period of the span in the the long haul it takes those voyagers to run those remaining 1/3. Accordingly the train must travel toward three times the running speed of the voyager. Train = 45 mph, voyagers = 15 mph.
The speed of P&D = 15 mph
Answer: There are 99 three-legged-cows and 28 chickens.
Step-by-step explanation:
Let x be the number of three-legged-cows and y be the number of chickens.
Number of legs in chicken = 2
The according to the question, we have the following equations :-
Multiplying 2 to the equation (1), we get
Now, subtract equation (3) from (2), we get
Put x= 99 in (1), we get
Hence, there are 99 three-legged-cows and 28 chickens.
Since we are adding two positive numbers here, their sum could be found by writing either
8
+4
---
12
or
4
+8
---
12