A graduated cylinder was filled with 25.0 mL of water. A solid object was immersed in the cylinder, raising the water level to 3
1 answer:
Answer:
Density of the object is 8759.494 grams/L
Explanation:
As we know density of an object is mass of the object divided by its volume
Given
Volume of the object is equal to the change in volume of water with in the cylinder when the object was immersed in water.
Hence, volume of object is equal to
mL
Mass of the object is grams
Density
grams/L
Density of the object is 8759.494 grams/L
You might be interested in
Answer:
75603.86473 K
Explanation:
Given that:
The 1st excited electronic energy level of He atom = 3.13 × 10⁻¹⁸ J
The objective of this question is to estimate the temperature at which the ratio of the population will be 5.0 between the first excited state to the ground state.
The formula for estimating the ratio of population in 1st excited state to the ground state can be computed as:
From the above equation:
Δ E = energy difference = 3.13 × 10⁻¹⁸ J
k = Boltzmann constant = 1.38 × 10⁻²³ J/K
Thus:
T = 75603.86473 K
Shape of PCl₆⁻¹, is octahedral.
Hybrdisation of PCl₆⁻¹ is sp³d².
This can be seen the image attached.
The angle between phosphorous and chlorine is 90⁰C. As it has octahedral geometry.
So the answer is as follows:
Shape of PCl₆⁻¹, is octahedral.
Hybrdisation of PCl₆⁻¹ is sp³d².
The angle between phosphorous and chlorine is 90⁰C.
