<em>Given that:</em>
mass of the ball (m) = 0.5 Kg ,
ball strikes the wall (v₁) = 5 m/s ,
rebounds in opposite direction (v₂) = 2 m/s,
time duration (t) = 0.01 s,
<em> Determine the force (F) = ?</em>
We know that from Newton's II law,
<em>F = m. a</em> Newtons
(velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>
= m × (v₁ + v₂)/t
= 0.5 × (5 + 2)/0.01
= 350 N
<em>The force acting up on the ball is 350 N</em>
Answer:
1. Why is Jupiter's rotation dangerous for human survivability?
<h2>=> </h2>
<em><u>Jupiter is the fastest rotating planet in our solar system. One day lasts about 9.5 Earth hours. This creates powerful winds that can whip around the planet at more than 300 mph. About 75 miles below the clouds, you reach the limit of human exploration.</u></em>
2 .Why is Jupiter's planet axis tilt an issue for human survivability?
<h2>=></h2>
<em><u>Jupiter, like Venus, has an axial tilt of only 3 degrees, so there is literally no difference between the seasons. ... The length of each season is roughly three years. Jupiter is the fastest spinning planet in our Solar System, which causes the planet to flatten at the poles and bulge at the </u></em><em><u>equator.</u></em>
3.Why is the diameter of Jupiter an issue for human survivability?
<h2>=></h2>
<em><u>Since </u></em><em><u>,</u></em><em><u>The </u></em><em><u>Jupiter </u></em><em><u>is </u></em><em><u>so </u></em><em><u>huge </u></em><em><u>in </u></em><em><u>mass</u></em><em><u> </u></em><em><u>,</u></em><em><u>The </u></em><em><u>central</u></em><em><u> </u></em><em><u>force</u></em><em><u> </u></em><em><u>toward</u></em><em><u> </u></em><em><u>the </u></em><em><u>centre </u></em><em><u>will </u></em><em><u>be </u></em><em><u>high</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>we'll</u></em><em><u> </u></em><em><u>be </u></em><em><u>forced</u></em><em><u> </u></em><em><u>toward</u></em><em><u> </u></em><em><u>it </u></em><em><u>causing</u></em><em><u> </u></em><em><u>Several</u></em><em><u> </u></em><em><u>problems</u></em><em><u>.</u></em>
Answer:
2.5705594546378 mol
Explanation:
Used this calculator
http://www.endmemo.com/chem/mmass.php