Answer:
Mg
Explanation:
If one were comparing just the neutral atoms Mg and S, the S atom would be smaller as both elements are in the same period and sulfur is more to the right
The answer is: when the aim is to show electron distributions in shells
An orbital notation is more appropriate if you want to show how the electrons of an atom are distributed in each subshell. This is because there are some atoms that have special electronic configurations that aren't obvious in just written configurations.
<h3><u>Answer</u>;</h3>
B. 3/2
<h3><u> Explanation;</u></h3>
Balance the chemical equation
2Al + 3Cl2 → 2AlCl3
We want to convert moles of AlCl3 to moles of Cl2
The conversion factor is 2 mol AlCl3/3 mol Cl2.
We choose the one that makes the units cancel:
x mol AlCl3 x (3 mol Cl3)/(2mol AlCl3) = x mol Al
The fraction for the molar ratio is 3/2.
1.d
2.g
3.j
4.i
5.c
6.h
7.e
8.b
9.a
10.f
Answer:
Aluminium.
Explanation:
The above electronic configuration can be written in a simplified form as shown below:
1s² 2s²2p⁶ 3s²3p¹
Next, we shall determine the number of electrons in the atom of the element as follow:
Number electron = 2 + 2 + 6 + 2 + 1
Number of electron = 13
Next, we shall determine the number of protons.
Since the element is in its neutral state,
The number of electrons and protons are equal i.e
Proton = Electron
Number of electron = 13
Proton = Electron = 13
Proton = 13
Next, we shall determine the atomic number of the element.
The atomic number of an element is simply the number of protons in the atom of the element i.e
Atomic number = proton number
Proton = 13
Atomic number = 13
Comparing the atomic number of the element with those in the periodic table, the element with the above electronic configuration is aluminium since no two elements have the same atomic number.