Answer: the length of string that been let out to fly the kite this high is 172.89 ft
Step-by-step explanation:
The length of string attached to the kite, the vertical height of the kite above the ground and the ground distance forms a right angle triangle.
With an angle of 57 degrees, the length of the string that is attached to the kite represents the hypotenuse of the right angle triangle.
The height of the kite above the ground represents the opposite side of the triangle
To determine h, the length of the string that has been let out to fly the kite this high, we would apply the
Sine trigonometric ratio which is expressed as
Sine θ = opposite side/hypotenuse
Sin 57 = 145/h
h = 145/Sin57 = 145/0.8387
h = 172.89
Hey there! :)
Since 2 4/5 is greater than 1/4, the answer is negative.
You can just subtract 2 4/5 and 1/4 and add the (-) sign
2 4/5 - 1/4
Change the fractions so they can have a common denominator: 20
2 4/5 = 2 16/20
1/4 = 5/20
2 16/20 - 5/20 = 2 11/20
Add the (-) sign → -2 11/20
Answer ⇒ -2 11/20
:)
Answer:
6(8 -5)
Step-by-step explanation:
take out the 6 -
8 - 5
then put them in parentheses
(8 - 5)
add back the 6
6(8 - 5)
Answer:
x = 6
Step-by-step explanation:
EG = 59
EF = 8x - 14
FG = 4x + 1
to find the value of x
EF + FG = EG (same line)
8x - 14 + 4x + 1 = 59
12x -13 = 59
12x = 59 + 13
12x = 72
x = 72 ÷ 12
x = 6
You can even cross check for correct answer
EF + FG = EG
instead of x place the x's value we got
8x - 14 + 4x + 1 = 59
8 (6) - 14 + 4 (6) + 1 = 59
48 - 14 + 24 + 1 = 59
34 + 25 = 59
59 = 59
CROSS - CHECKED
1,2,3,4 are the domain. The x column is always the domain.