(i) |α| = 235.6rad.s / 0.502s = 469 rad/s²
(ii) tang a = α*r = 469rad/s² * 0.12m / 2*11 = 2.56 m/s²
We know that the electric field is equal to 1 E 6 V/m
The distance between the thundercloud and the ground is 1.6km = 1600m
Electric field = Voltage/distance
This means that the breakdown voltage must be equal to
V = 1 E 6 V/m * 1600m = 1.6 E 9 V = 1.6 GV
Answer with Explanation:
We are given that
Fundamental frequency,f=88.4 Hz
Speed of sound,v=343 m/s
We have to find the first three overtones.
Tube is closed
The overtone of closed pipe is equal to odd number of fundamental frequency.
Therefore, the overtone of tuba
Where n=3,5,7,..
Substitute n=3
For second overtone
For third overtone
True. Classifying by similarities is the basis for biological classification.