Answer:
The length of the rectangle (l) = 3 feet
The width of the rectangle (W) = 10 feet
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the width of the rectangle = (x+1) feet</em>
<em>Given that the length of the rectangle = ( x-6) feet</em>
<em>The area of the rectangle = 30 square feet</em>
<u><em>Step(ii):-</em></u>
We know that the area of the rectangle
= length ×width
30 = ( x+1)(x-6)
30 = x² - 6x + x -6
⇒ x² - 5 x - 6 = 30
⇒ x² - 5 x - 6 - 30 =0
⇒ x² - 5 x - 36 =0
x² - 9 x +4x - 36 =0
x (x-9) +4 ( x-9) =0
( x+4 ) ( x-9) =0
( x+4 ) =0 and ( x-9) =0
x =-4 and x =9
<u><em>Step(iii):-</em></u>
we have to choose x =9
The length of the rectangle (l) = x-6 = 9-6 =3
The width of the rectangle (W) = x+1 = 9 +1 = 10
<u><em>Final answer:-</em></u>
The length of the rectangle (l) = 3 feet
The width of the rectangle (W) = 10 feet
We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2
This means, there can be 15 different combinations of 2 members that can sit in the front row.
So, the answer to this question is option A
Step-by-step explanation:
= -4 + 12 + (-9)
= -4 + 12 - 9
= -4 + 3
= -1
So you can play? I guess...
