78 = 2 x 3 x 13
1 x 78
2 x 39 = 78
3 x 26=78
6 x 13 = 78
larger number is 13
Answer:
0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
(-5x + 6x²) - (6x² - 5x)
<u>Step 2: Simplify</u>
- [Distributive Property] Distribute negative: -5x + 6x² - 6x² + 5x
- [Subtraction] Combine like terms (x²): -5x + 5x
- [Addition] Combine like terms (x): 0
Answer:
Large umber is 11, small one 7
Step-by-step explanation:
11- 4 =7
7+11=18
3x+4=x+2
2x+4=2
2x=-2
-2/2
X=-1
Y=-1+2
Y= 1
Solution= (-1,1)
Answer:
15 seconds.
Step-by-step explanation:
∵ The distance covered by plane in first second = 100 ft,
Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,
So, distance covered in second second = 200,
In third second = 300,
In fourth second = 400,
............, so on....
Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds
( Sum of AP )
Suppose the distance covered in n seconds is 12,000 feet,
∵ n can not be negative,
Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.