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2 years ago

Question 1:

Mathematics

2 answers:

valkas [14]2 years ago

7 0

Answer:

2. 674

Step-by-step explanation:

6+67+674=747

DochEvi [55]2 years ago

6 0

Answer:

1. 29

2. 674

Step-by-step explanation:

for the second one 6+67+674=747

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Meredith has a recipe that makes 24 cupcakes but she wants to make double batch. The original recipe calls for twice as much flo

pickupchik [31]

Answer:

she would need 2 cups flower for a double batch.

Step-by-step explanation:

Flower = 2x sugar

Sugar = 1/2 cup

Flower = 1 cup (for the original recipe)

then you double it = 2 cups flower

4 0

2 years ago

Pedro, Lena, Harriet, and Yermin each plot a point to approximate StartRoot 0.50 EndRoot. Pedro A number line going from 0 to 0.

Scilla [17]

Answer:

Yermin. √0.5 will be at Yermin's point

Step-by-step explanation:

Say Pedro line point is 0.25

Lena is 0.45

Harriet is 0.5

and Yermin is 0.7

The √0.5 = 0.707

≈ 0.7

Therefore it is at Yermin's point

5 0

2 years ago

Read 2 more answers

Mean = 5 13+14+15+19+19 =

Gelneren [198K]

Answer:

14.167

Step-by-step explanation:

assuming you meant 5+13

7 0

1 year ago

Which<br> graph shows a dilation?

lukranit [14]

The second one from the top shows a dilatation.

6 0

1 year ago

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0

2 years ago

Read 2 more answers