To determine the amount of water in the first 8 beakers, you will subtract the 19 ml that are in the 9th beaker from the total to see how much water was actually put into the first 8 beakers.
91 ml - 19 ml = 72 ml.
The 72 ml are divided evenly between 8 beakers.
72/8 = 9 ml
There would be 9 ml of water in each of the first 8 beakers.
Scientific notation is a way to write compactly numbers with lots of digits, either because they're very large (like 2393490000000000000000000), or very small (like 0.0000000000356).
We use powers of ten to describe all those leading/trailing zeros, so that we con concentrate on the significat digits alone.
In your case, the "important" part of the number is composed by the digits 6 and 1, all the other digits are zero. But how many zeroes? Well, let's do the computation.
Every power of 10, is written as one zero followed by n zeroes, so we have
Multiplying a number by means to shift the decimal point to the right and/or add trailing zeroes n times. So, we have to repeat this process six times. We shift the decimal point to the right one position, and then add the five remaning zeroes. The result is thus
Answer:
30 weeks
Step-by-step explanation:
105-90
=15 kg
15kg= 15000g
15000g/500g
=30 weeks
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Answer: -5x^3 -13x^2 -6x + 15ix + 39ix + 18i
Step-by-step explanation:
An equation with zeros at these numbers could be put in form x = number.
So, (x-3) could be set to 0 to get x=3.
So, you can look at these "answers" they give you and work backward to get:
(x-3)(x+2/5)(x-3i)
Multiply first two together.
x^2+2/5x-3x-6/5
simplify
x^2 - 2 3/5x -6/5
Change first term to have same denominator by multiplying by "1" in the form of -5/-5
-5x^2/-5 - 13/5x -6/5
Divide all terms by 1/5 (which is the same as multiplying each term by 5)
(-5x^2 -13x -6)
Now multiply by (x-3i)
-5x^3 -13x^2 -6x + 15ix + 39ix + 18i
Answer:
Step-by-step explanation:
The equation is y = -4x²
Next time, please share the answer choices.
Here's a short table of possible solutions:
x -x² (x, y)
----- ------ ---------
0 0 (0, 0)
2 -4 (2, -4)
-3 -9 (-3, -9)