Answer:
Not sure for 1. Area might be 144. Perimeter might be 50. I got perimeter by finding slant height of the parallelogram and then substituting it to the perimeter formula (P=2(a+b) where a is a side and b is a base). I found area by just multiplying 12*12 since to find area of parallelogram, it is base x height.
2. 45, 135, 135
Step-by-step explanation:
2. We know that an isosceles trapezoid has congruent base angles and congruent upper angles, so if one base angle measures 45 degrees, the other base angle will also be 45 degrees.
For the upper angles, we know that diagonal angles are supplementary, so 180- base angle 1 (45 degrees)= upper angle 1
180-45=upper angle 1
upper angle 1 = 135 degrees
Mentioned above, upper angles are congruent, so upper angles 1 and 2 will be 135 degrees.
Check: The sum of angles in a quadrilateral is equal to 360 degrees. We can use this to check if our answer is correct.
135+135=270 degrees (sum of upper angles)
45+45= 90 degrees (sum of base angles)
270+90=360
So the angle measures of the other three angles are 135, 135, and 45.
Hope this helps!
Answer:
D. Associative Property
Step-by-step explanation:
The group is being switched around.
Answer:
![\sqrt[4]{2}^{3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B2%7D%5E%7B3%7D)
Step-by-step explanation:
1) function f(x)
x - 5
f(x) = ----------------
3x^2 - 17x - 28
2) factor the denominator:
3x^2 - 17x - 28 = (3x + 4)(x - 7)
x - 5
=> f(x) = -----------------------
(3x + 4) (x - 7)
3) Find the limits when x → - 4/3 and when x → 7
Lim of f(x) when x → - 4/3 = +/- ∞
=> vertical assymptote x = - 4/3
Lim of f(x) when x → 7 = +/- ∞
=> vertical assymptote x = 7
Answer: there are assympotes at x = 7 and x = - 4/3
