I am almost positive that it is 360
Let
x--------------> a number
we know that
<span>three sets of a sum of a number and four----------> 3(x+4)
t</span><span>he sum of 7 times the same number and 13--------> 7x+13
therefore
</span>(Three sets of a sum of a number and four) are added (to the sum of 7 times the same number and 13) ----------> [3(x+4)] + [7x+3]
[3(x+4)] + [7x+3]------> [3x+12] + [7x+3]=10x+15
the answer is 10x+15
Answer:
D) a8 = 35 - (n - 1)(3)
Step-by-step explanation:
Yes it can. It doesn't <em>have to be</em>, but it can be without too much trouble.
In fact, ALL rhombuses are quadrilaterals.
