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2 years ago

I'm not sure if this is right or not could someone also explain why ?

Mathematics

1 answer:

nikitadnepr [17]2 years ago

6 0

The mapping rule for 90 degrees counterclockwise would be (-y,x). So if you had (x,y) it would transfer to (-y,x). Yours is wrong it should be (4,-3). Remember
-(-4) is 4 and -3 stays as -3.

Basically, memorize these mapping rules.

Hope this helped!

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2 years ago

Ten large marbles weigh as much as 14 small marbles. How many large marbles weigh as much as 35 small marbles?

Paladinen [302]

To get the answer we can use proportion
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x large -------------- 35 small
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2 years ago

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If c(x)=5/x-2 and d(x)=x+3 what is the domain of (cd)(x)?. . And, if f(x)=7+4x and g(x)=1/2x, what is the value of (f/g)(5)?

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1. The value of (cd)(x) is equal to the product of c(x) and d(x) which is equal to,
5(x + 3) / (x - 2)
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3 years ago

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Sara has 20 sweets. She has 12 liquorice sweets, 5 mint sweets and 3 humbugs. Sarah is going to take, at random, two sweets Work

Debora [2.8K]

Answer:

111 / 190

Step-by-step explanation:

Let us first compute the probability of picking 2 of each sweet. Take liquorice as the first example. There are 12 / 20 liquorice now, but after picking 1 there will be 11 / 19 left. Thus the probability of getting two liquorice is demonstrated below;

$12 / 20 * 11 / 19 = \frac{33}{95},\\Probability of Drawing 2 Liquorice = \frac{33}{95}$

Apply this same concept to each of the other sweets;

$5 / 20 * 4 / 19 = \frac{1}{19},\\Probability of Drawing 2 Mint Sweets = 1 / 19\\\\3 / 20 * 2 / 19 = \frac{3}{190},\\Probability of Drawing 2 Humbugs = 3 / 190$

Now add these probabilities together to work out the probability of drawing 2 of the same sweets, and subtract this from 1 to get the probability of not drawing 2 of the same sweets;

$33 / 95 + 1 / 19 + 3 / 190 = \frac{79}{190},\\1 - \frac{79}{190} = \frac{111}{190}\\\\$

The probability that the two sweets will not be the same type of sweet =

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2 years ago

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Answer:

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