Answer:
<h3>Q1</h3>
The graph of y = f(x), has vertex at (1, -2)
<u>The vertex of a function f(x - 3) is going to be:</u>
<h3>Q2</h3>
- <em>The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).</em>
The axis of symmetry is at the same distance from the symmetric points.
x = 5 is a vertical line. The point (8, -7) is 3 units to the right. So the mirror point will be 3 units to the left and have same y-coordinate: x = 5 - 3 = 2
The point is (2, -7)
<h3>Q3</h3>
The graph in blue is the translation of the red to the left by 2 units.
<u>So the equation is:</u>
<h3>Q4</h3>
y = h(x) is graphed
- h(7) = 5
- h(h(7)) = h(5) = -1
<h3>Q5</h3>
The graph of the function y = u(x) given
This is a odd function.
The coordinates of u(x) and u(-x) add to zero because u(-x) = -u(x)
<u>Therefore:</u>
- u(-2.72) + u(-0.81) + u(0.81) + u(2.72) =
- [u(-2.72) + u(2.72)] + [u(-0.81) + u(0.81)] =
- 0 + 0 = 0
